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A bottle of coins with $8.10 in it. there was an equal amount of dimes,quarters&silver coins how many of each?

Question: A bottle of coins with $8.10 in it. there was an equal amount of dimes,quarters&silver coins how many of each?

(Posted by: ecblingbling on 2006-01-27 16:56:11)

A bottle of coins sat on the table. when it was opened,there was a total of $8.10. there was an equal number of dimes,quarters and silver dollars,but no other denominations of coins. how many of each?


Answers:

Posted by: Angelo on 2006-01-27,17:00:24

6 you have to do .10x+ .25x+ 1x= 8.10 and solve for x

  

Posted by: escapegrl1 on 2006-01-27,17:12:15

6 each. 1X + .25X + .10X = 8.10 1.35X = 8.10 X = 8.10/ 1.35 x= 6

  

Posted by: KT on 2006-01-27,17:22:18

25x+ 100x+ 10x= 810 135x/ 135= 810/ 135 x= 6

  


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